it looks like;

%1 - archive filename
%2 - file to pack, file to extract, etc
%3 - destination dir (probably \mystic\temp<node>\)

~~~but~~~ the one example we do have for the view command looks like this:
7z l -y "%1" >> "%3$2"

which looks an awful lot like it redirects 7z output to: \mystic\temp<node>\filename it knows to display

so perhaps:

Sorry I do not use 7Z and I stick with the 80 standard archivers like pkzip, pkunzip, arj and arc.

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On 06 Mar 2026, Phil Taylor said the following...

Sorry I do not use 7Z and I stick with the 80 standard archivers like pkzip, pkunzip, arj and arc.

dude do you try to learn how anything works in your life? or are you just treating this echo like a personal ChatGPT with real people on the other side?

"new" knowledge can be created by learning two different things and then realizing how they relate. this is why i gave the 7zip example

this: 7z l -y "%1" >> "%3%2"

you take this and you look at the 7zip parameter printout:

<Commands>
..
l : List contents of archive
..

<Switches>
-y : assume Yes on all queries

okay, so let's plug in the parameters from our example as they are filled in from this list:

%1 - archive filename
%2 - file to pack, file to extract, etc
%3 - destination dir (probably \mystic\temp<node>\)

7z l -y "coolfile.7z" >> "c:\mystic\temp1\tempfile.arc"

so it would seem it runs 7zip to list the archive contents, and just in case 7z.exe asks any questsions it just makes sure they're answered 'yes'.

the ">>" redirects output from a program to a file, and if it exists it's overwritten

everything after that is the file the output of 7z.exe is written to (the actual listing of files in the archive as if you typed that out on the command line)

now after that command is done, mystic reads the file that 7z just output to and prints it to the user (see my other message where i spelled this out pretty clearly)

so taking what we've learned, you should be able to figure out what parameters to pass to arj. but the most embarrassing part:

THE PARAMETERS TO ARJ.EXE ARE THE EXACT SAME. 7ZIP'S COMMAND LINE IS MODELED AFTER ARJ'S

arj l -y "%1" >> "%3%2"

please, please, please at least try to apply some brain power to what you're doing.

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On 06 Mar 2026, Phil Taylor said the following...

Sorry I do not use 7Z and I stick with the 80 standard archivers like pkzip, pkunzip, arj and arc.

dude do you try to learn how anything works in your life? or are you just treating this echo like a personal ChatGPT with real people on the other sid

"new" knowledge can be created by learning two different things and then realizing how they relate. this is why i gave the 7zip example

this: 7z l -y "%1" >> "%3%2"

you take this and you look at the 7zip parameter printout:

<Commands>
..
l : List contents of archive
..

<Switches>
-y : assume Yes on all queries

okay, so let's plug in the parameters from our example as they are filled in from this list:

%1 - archive filename
%2 - file to pack, file to extract, etc
%3 - destination dir (probably \mystic\temp<node>\)

7z l -y "coolfile.7z" >> "c:\mystic\temp1\tempfile.arc"

so it would seem it runs 7zip to list the archive contents, and just in case 7z.exe asks any questsions it just makes sure they're answered 'yes'.

the ">>" redirects output from a program to a file, and if it exists it's overwritten

everything after that is the file the output of 7z.exe is written to (the actual listing of files in the archive as if you typed that out on the comma line)

now after that command is done, mystic reads the file that 7z just output to and prints it to the user (see my other message where i spelled this out pre clearly)

so taking what we've learned, you should be able to figure out what paramete to pass to arj. but the most embarrassing part:

THE PARAMETERS TO ARJ.EXE ARE THE EXACT SAME. 7ZIP'S COMMAND LINE IS MODELED AFTER ARJ'S

arj l -y "%1" >> "%3%2"

please, please, please at least try to apply some brain power to what you're doing.

It does not work because when I try and view a file I get

Unable to view archive.

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